show that the points A(1,2), B(-1,-16) and C(0,-7) lie on the graph of the linear equation y=9x-7.
If the points A(1, 2), B(–1, –16) and C(0, –7) lie on the graph of the linear equation y = 9x – 7 then the these points should satisfy the equation of the given line.
Let us check it:
For point A(1, 2),
Here, x = 1 and y = 2, therefore
y = 9x – 7
⇒ 2 = 9 (1) – 7
⇒ 2 = 2
Thus, point A lies on the given line.
For point B(–1, –16)
Here, x = –1 and y = –16, therefore
y = 9x – 7
⇒ –16 = 9 (–1) – 7
⇒ –16 = –16
Thus, point B lies on the given line.
For point C(0, –7),
Here, x = 0 and y = –7, therefore
y = 9x – 7
⇒ –7 = 9 (0) – 7
⇒ –7 = –7
Thus, point C lies on the given line.
Hence, all three points A, B and C lie on the line y = 9x – 7.