show that the points A(1,2), B(-1,-16) and C(0,-7) lie on the graph of the linear equation y=9x-7.

If the points A(1, 2), B(–1, –16) and C(0, –7) lie on the graph of the linear equation y = 9x – 7 then the these points should satisfy the equation of the given line.

Let us check it:

For point A(1, 2), 

Here, x = 1 and y = 2, therefore

y = 9x – 7 

⇒ 2 = 9 (1) – 7 

⇒ 2 = 2

Thus, point A lies on the given line.

For point B(–1, –16) 

Here, x = –1 and y = –16, therefore

y = 9x – 7 

⇒ –16 = 9 (–1) – 7 

⇒ –16 = –16 

Thus, point B lies on the given line.

For point C(0, –7), 

Here, x = 0 and y = –7, therefore

y = 9x – 7 

⇒ –7 = 9 (0) – 7 

⇒ –7 = –7 

Thus, point C lies on the given line.

Hence, all three points A, B and C lie on the line y = 9x – 7. 

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