Show that square of any positive odd integer is of the form 8m + 1, for some integer m.

Dear Student!

Here is the answer to your question.

Any odd positive integer is of the form 4

*q*+ 1 or 4*q*+ 3 for some integer*q*.When

*n*= 4*q*+ 1,⇒

*n*^{2}is in the form 8*m*+ 1Hence,

*n*^{2}is in the form 8*m*+ 1 if*n*is an odd positive integer.Cheers!

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