show that for sets A and B , A=(A intersection B)U(A-B) and A U (B-A)=AUB Share with your friends Share 4 Neha Sethi answered this Dear student To prove:A=A∩B∪A-BConsider, A∩B∪A-B=A∩B∪A∩B' as A-B=A∩B'=A∩B∪B' distributive law=A∩X B∪B'=X=A where X is universal setSo, A=A∩B∪A-BHence proved.Now to prove :A∪B-A=A∪BConsider, A∪B-A=A∪B∩A' as B-A=B∩A'=A∪B∩A∪A' distributive law=A∪B∩X where X is universal set=A∪B Regards 4 View Full Answer
