Resistance of a given wire of length 'L' is 42. The wire is stretched uniformly such that its length becomes 3L. Find the new resistance of the stretched wire. Share with your friends Share 0 Vipra Mishra answered this Solution Here volume of the wire will be same in both the condition hencevolume =A1 L1 = A2L2AL =A23LA2 =A3new area of cross section of wire =A3 after changing length three times hence new resistance R=ρ3LA/3=9ρLA=9×42=378 ohm 0 View Full Answer
