Question number 23 ii part

Question number 23 ii part x (iii) a a (iv) al (i) a—b a x a a x bc = (x + 2a) (x — a)2. = a3 + b3 + c3 — 3abc. (CBSE, DB 2 (ii) a—c ac + c ac = 4a2b2c2. a + ab

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