Question-9
Q.9. In the Fig., given below ABCD is a parallelogram and if A B P Q C D , prove that M R B C .

In △MPQ,

AB / PQ = MA / MP                             

=> CD / PQ = MA / MP                         [ ... AB = CD (sides of a | |gm) ]

But, In △RPQ,

CD / PQ = RD / RP                               

Therefore, MA / MP = RD / RP

=> AD | | MR
=> BC | | MR                                      [... AD | | BC (sides of a | |gm) ]

This was just a hint on how to solve this question. You need to do the necessary steps ( like proving triangles similar ) in between. I am prretty sure you will be able to do that.

Hope. . it helps you
  • 3
Thanks Himanshu
  • 2
What are you looking for?