dear student let the points be A(1,-1) and B (-2,m)and O be the originthenOA⇀=i⇀-j⇀OB⇀=-2i⇀+mj⇀for a⇀ and b⇀ to be collinearOB⇀=k OA⇀-i⇀-j⇀=-2ki⇀+mkj⇀so, -1=-2k and -1=mkputting k=1/2m=-2 regards

Question 5

dear student

l e t t h e p o i n t s b e A (1, - 1) a n d B (- 2, m) a n d O b e t h e o r i g i n t h e n \overset{⇀}{O A} = \overset{⇀}{i} - \overset{⇀}{j} \overset{⇀}{O B} = - 2 \overset{⇀}{i} + m \overset{⇀}{j} f o r \overset{⇀}{a} a n d \overset{⇀}{b} t o b e c o l l i n e a r \overset{⇀}{O B} = k . \overset{⇀}{O A} - \overset{⇀}{i} - \overset{⇀}{j} = - 2 k \overset{⇀}{i} + m k \overset{⇀}{j} s o, - 1 = - 2 k a n d - 1 = m k p u t t i n g k = 1 / 2 m = - 2

regards

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