Qno 1 Qno 1 Exervise for Session 2 continuity - Share with your friends Share 0 Aarushi Mishra answered this fx=-2 sin x, for -π≤x≤-π2 a sin x+b, for -π2<x<π2cos x, for π2≤x≤πFor fx to be contiuous at x=klimx→k+ fx=limx→k- fx=fkFor fx to be continuous at x=π2limx→π2+ fx=limx→π2- fx=fπ2fπ2=cos π2=0limx→π2- fx=0For x<π2, fx=a sin x+blimx→π2- a sin x+b=0 a sin π2+b=0a+b=0 _________1For fx to be continuous at x=-π2limx→-π2+ fx=limx→-π2- fx=f-π2f-π2=-2 sin -π2=2 sin π2=2limx→-π2+ fx=2For x>-π2, fx=a sin x+blimx→-π2+ a sin x+b=2a sin -π2+b=2-a+b=2 _________2Adding equation 1 and 22b=2b=1a+b=0a=-b=-1 0 View Full Answer