Q32. In the circuit below, capacitors A and B have identical geometry, but a material of dielectric constant 3 is present between the plates of B. The potential differences across A and B are, respectively
A/Q if capacitance of A = C then capacitance of B = 3C
so net C = C(3C)/C+3C = 3C/4
and net Q = 3C/4*10 = 15C/2
PD across A = Q/C = 15/2 = 7.5
and PD across B = (15C/2)/3C = 2.5