Q32

Q32. In the circuit below, capacitors A and B have identical geometry, but a material of dielectric constant 3 is present between the plates of B. The potential differences across A and B are, respectively

          (a) 2.5 V, 0.5 V

          (b) 2 V, 8 V

          (c) 7.5 V, 2.5 V

          (d) 8 V, 2 V​
                                    
 

Dear student,capacitance of A=Ccapacitance of B=3C due to dilectric of value 3Cnet=34CNet charge from battery=34C×10=304CPotential difference across A=304CC=7.5VPotential difference across B=304C3C=2.5VRegards

  • 3
A/Q if capacitance of A = C then capacitance of B = 3C
so net C = C(3C)/C+3C = 3C/4
and net Q = 3C/4*10 = 15C/2
PD across A = Q/C = 15/2 = 7.5
and PD across B = (15C/2)/3C = 2.5
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