Q25

Q25 SHOT ON MI A1 MI DUAL CAMERA



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https://www.meritnation.com/ask-answer/question/in-a-rhombus-abcd-show-that-ac2-bd2-4-ab2/circles/203419​ 

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Proof of pythagoras thm.

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can u clearify what to prove . picture is not taken good
 
  • 0
After DC×AC-- BC2

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now , 
let O be point where the diagonals bisect each other perpendicularly ,

that is ,

2AO = AC AND 2BO = BD 
squaring both sides,

4AO2=AC2  AND 4BO2=BD2

AO2=AC2/4 AND BO2=BD2/4

then,
in tria.AOB ,

AB2= AO2 + BO2                                  by pythagores 

AB2=AC2/4 + BD2/4

AB2= [AC2+BD2]/4

4AB2=AC2+BD

HENCE PROVED :-]
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