Q16. In an equilateral triangle, prove that three times the square of one side is equal to four times  the square of one of its altitudes.

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16)

Given: Equilateral triangle ABC with each side a and AD as one of its altitudesTo prove: 3×Square of one side=4×Square of one of it's altitude3a2=4AD2Proof:In ADB and ADCAB=AC   Both are a as it is equilateral AD=AD   (common)ADB=ADC   Each 90°Hence ADBADC   By R.H.S congruencyHence, BD=DC    CPCTBD=DC=12BCBD=DC=a2     ...(1)Now, ADB is a right-angled Using Pythagoras theoremAB2=AD2+BD2a2=AD2+a22    using 1AD2=a2-a24AD2=3a244AD2=3a2Hence proved

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