Q15. A car travelling at 36 km/hr due North tums West in 5 s under constant acceleration maintains the same speed. The acceleration of the car is
(A) 2 m/s2 South-West (B) 10 m/s2 North-East
(C) 2 m/s2 South.East (D) 5 m/s2 North-West
Initial velocity of car=36km/h=10m/s in north direction=10j
Final velocity of car=10 m/s in west direction=-10i
where i and j are the unit vectors along x axis and y axis respectively.
Change in velocity=-10i-10j
Acceleration =Change in velocity/Time taken