Q15. A car travelling at 36 km/hr due North tums West in 5 s under constant acceleration maintains the same speed. The acceleration of the car is 

              (A) 2 2  m/s2 South-West                                 (B) 10 m/s2 North-East

              (C) 2 2  m/s2 South.East                                   (D) 5 m/s2 North-West

Dear Student ,
Initial velocity of car=36km/h=10m/s in north direction=10j

Final velocity of car=10 m/s in west direction=-10i

where i and j are the unit vectors along x axis and y axis respectively.

Change in velocity=-10i-10j


Acceleration =Change in velocity/Time taken


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