Q1. Three atoms A, B & C crystallize in a cube solid lattice where A atoms are present at B.C. B atoms are present at E.C. as well as at corners of the cube & C atoms are present at F.C. of the cube. Now if all the atoms are removed from the two 4 - fold axis and the one  α - fold axis passing through the cube, formula of the compound is
(a) B7C2                                ‚Äč(b) AB2C7
(c) ABC2                               (d) A5C2
 

Dear Student,
In the Question, No of the axis of symmetry is not clear so I am solving the question that  atoms are removed from 2 four-fold axis of symmetry and  2 two-fold axes of symmetry
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Regards

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