# Q1. Three atoms A, B & C crystallize in a cube solid lattice where A atoms are present at B.C. B atoms are present at E.C. as well as at corners of the cube & C atoms are present at F.C. of the cube. Now if all the atoms are removed from the two 4 - fold axis and the one $\alpha$ - fold axis passing through the cube, formula of the compound is (a) B7C2                                ​(b) AB2C7 (c) ABC2                               (d) A5C2

Dear Student,
In the Question, No of the axis of symmetry is not clear so I am solving the question that  atoms are removed from 2 four-fold axis of symmetry and  2 two-fold axes of symmetry

Regards

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