Q: The value of 4π∫0^(π/2)▒cosx/(cosx+sinx) dx is equal to Share with your friends Share 0 Manbar Singh answered this Let I = ∫0π/2cos xcos x + sin x dx ....1⇒I = ∫0π/2cos π/2-xcos π/2-x + sin π/2-x dx ⇒I = ∫0π/2sin xsin x + cos x dx .....2Adding 1 and 2, we get2I =∫0π/2sin x + cos xsin x + cos x dx ⇒2I =∫0π/2 dx⇒2I = x0π/2 ⇒2I = π2-0⇒I = π4now, 4π∫0π/2cos xcos x + sin x dx = 4I = 4 × π4 = π 0 View Full Answer
