Q. In the given figure, ABCD and AEFG are two squares. Prove that (i) AF/AG =AC/AD (ii) triangle ACF ~ triangle ADG. Share with your friends Share 5 Aarushi Mishra answered this In the figureAG=GF sides of a squareAD=DC sides of a squareDividing bothAGAD=GFDCIn ∆ADC and ∆AGFAGAD=GFGC∠AGF=∠ADC=90° INTERIOR ANGLES OF A SQUARE∆ADC~∆AGF by SASTherefore we haveACAF=ADAGorAFAC=AGADorAFAG=ACAD _________1Hence proved iFrom the figure ∠GAF=45°∠DAC=45°∠DAC=∠GAF∠DAC-∠GAC=∠GAF-∠GAC∠DAG=∠CAF _________2In ∆ACF and ∆ADGAFAG=ACAD from equation 1∠DAG=∠CAF from equation 2By SAS, ∆ACF~∆ADG 17 View Full Answer
