# Q. If the angles of a triangle ABC are in the ratio 2:3:4, find the measure of the angles A,B, C.

Let common multiple be x then angle will be in the ratio of 2x:3x:4x.

Now in the triangle , sum of 3 angles will be 180

^{o}.

$\Rightarrow 2x+3x+4x=180\phantom{\rule{0ex}{0ex}}\Rightarrow 9x=180\phantom{\rule{0ex}{0ex}}\Rightarrow x=20\xb0\phantom{\rule{0ex}{0ex}}Anglewillberespectively40\xb0,60\xb0and80\xb0respectively.\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Regards$

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