Q For what value of λ, is the function defined byfx=λx2-2x: x≤04x+1 - Maths - Continuity and Differentiability

Question

Q   F o r   w h a t   v a l u e   o f  
λ ,   i s   t h e   f u n c t i o n   d e
f i n e d   b y f x = λ x 2 - 2 x :      
  x ≤ 0 4 x + 1          
    :         x > 0    
    W h a t   a b o u t   c o n t i n u i t y
  a t   x = 1

Rishabh Mittal · Accepted Answer

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Q . F o r w h a t v a l u e o f λ , i s t h e f u n c t i o n d e f i n e d b y f x = λ x 2 - 2 x : x ≤ 0 4 x + 1 : x > 0 W h a t a b o u t c o n t i n u i t y a t x = 1 .

$Q . F o r w h a t v a l u e o f λ, i s t h e f u n c t i o n d e f i n e d b y f (x) = \{\begin{cases} λ (x^{2} - 2 x) : x \leq 0 \\ 4 x + 1 : x > 0 \end{cases} W h a t a b o u t c o n t i n u i t y a t x = 1 .$