Q: ∫(e1/x+1)/x2 dx is equal to Share with your friends Share 0 Manbar Singh answered this Let I = ∫e1/x + 1x2 dxPut 1x = t⇒-1x2dx = dt⇒1x2dx = -dtNow, I = ∫-et+1 dt=- et - t + C=-e1/x - 1x +C 0 View Full Answer
