Q.5. In the different experiments, α -particles, proton, deuteron and neutron are projected towards gold nucleus with the same kinetic energy. The distance between closest approach will be minimum for
(A) α -particle
(B) proton
(C) deutron
(D) neutron

Dear Student,

Distance of closest approach, r=14πε0qQK.E.Here Q is the charge of gold foilOnly q is different, rest everything is constantSo, we can say thatr α qThe Value of q for :proton=1.6×10-19neutron=0deutron=1.6×10-19alpha particle=2×1.6×10-19=3.2×10-19 CSince value of q is greater for alpha particleSo, the correct answer is (A)

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