Q.5. In the different experiments, α -particles, proton, deuteron and neutron are projected towards gold nucleus with the same kinetic energy. The distance between closest approach will be minimum for (A) α -particle (B) proton (C) deutron (D) neutron Share with your friends Share 5 Vartika Jain answered this Dear Student, Distance of closest approach, r=14πε0qQK.E.Here Q is the charge of gold foilOnly q is different, rest everything is constantSo, we can say thatr α qThe Value of q for :proton=1.6×10-19neutron=0deutron=1.6×10-19alpha particle=2×1.6×10-19=3.2×10-19 CSince value of q is greater for alpha particleSo, the correct answer is (A) -16 View Full Answer