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Q.4. Find equivalent resistance between terminals A and D in following circuit.

The equivalent resistance between th epoints A and D are :

${R}_{AD}=5+\frac{\left(10+10\right)\times \left(10+10\right)}{10+10+10+10}+5\phantom{\rule{0ex}{0ex}}=5+\frac{400}{40}+5\phantom{\rule{0ex}{0ex}}=5+10+5\phantom{\rule{0ex}{0ex}}=20\Omega $

Regards

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