Q.36. A man has 10 friends and wants to arrange them on chairs taking 6 at a time. Find the number of arrangements, such that (i) two particular friends are always taken (ii) four particular friends are never taken. Share with your friends Share 1 Koka Sri Lakshmi Divya Sai answered this Dear Student (i)Number of friends a man have is 106 friends are to be taken at a time in which two particualar friends are always takenso these 2 friends are arranged in P26 waysNow the remaining 4 friends can be arranged by using remaining (10-2) friends in P(10-2,6-2) ways=P48Total Number of ways= P26× P48=50400(ii) Number of friends a man have is 106 friends are to be taken at a time such that four particular friends are never takenso, these four friends are arranged by using remaining (10-4)=6 friendsthis can be done in P(6,6)∴Number of ways=P66 =720 Regards 0 View Full Answer
