Q.30. A refrigerator based on Carnot cycle receives heat from 227$°$C and rejects heat at 727$°$C. Let the work input required per unit heat received is x. If the same machine is used as a Carnot engine, then its efficiency is y. The ratio of x and y is (1) 2 (2) 1 (3) 3 (4) $\frac{1}{2}$

Dear Student ,
Here in this case , from the given data we can write that ,

$\frac{x}{y}=\frac{227+273}{727+273}=\frac{500}{1000}=\frac{1}{2}$
Regards

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