Q.24. Find the area of the following figure.

Dear student


Clearly BDE is a right angled triangle So, by pythagoras theoremBD2=BE2+DE2BD2=82+62BD2=64+36BD2=100BD=100BD=10 unitsAlso, AC=BD=10 unitsNow, area of figure=Area of ABCD+Area of BED=AC×CD+12×BE×DE=10×12+12×8×6=120+24=144 sq units
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