Q 14 Potential in the x-y plane is given as V = - 10 (x2 + y) volts - Physics - Electrostatic Potential And Capacitance

Question

Q 14 Potential in the x-y plane is given as V = - 10 ( x 2 + y)
volts The electric field at the point (1 m, 1 m) will be
(1) 10 5 V/m
(2) 10 3 V/m
(3) 20 V/m
(4) 10 V/m

Sakshi Kanwar · Accepted Answer

Dear Student

Potential is =(-10x2-10y)Electric field=-dVdxwhen x is differentiated y is constant and vice versaE=-20x when y is constantE=-10( when x is constant)For x=1,y=1Enet=202+102=105V/mOption 1 is correctREGARDS

Q.14. Potential in the x-y plane is given as V = - 10 ( x 2 + y) volts. The electric field at the point (1 m, 1 m) will be (1) 10 5 V/m (2) 10 3 V/m (3) 20 V/m (4) 10 V/m

Q.14. Potential in the x-y plane is given as V = - 10 ( $x^{2}$ + y) volts. The electric field at the point (1 m, 1 m) will be
(1) 10 $\sqrt{5}$ V/m
(2) 10 $\sqrt{3}$ V/m
(3) 20 V/m
(4) 10 V/m