Q.1. An element X (2,8,2) combines separately with NO3 and (SO4)2 -, (PO4)3 - radicals.
a) On adding the number of electron of X, it is 12 which indicate Magnesium. It combine with NO3¯ and SO42¯to form Mg(NO3)2 and Mg(SO4). Magnesium belongs to 2nd group which forms ionic compound due to its metallic character.
b) 12X = 2 8 2 ; 16Y = 2 8 6
X = Magnesium = 2nd group and 3 period
Y = Sulphur = 6th-A group and 3 period
The bond formed will be ionic in nature because magnesium is metallic and sulphur is non-metallic.
Ans 1 - Magnesium is the compound. It belongs to the 2nd group of the periodic table. The compond it forms with the radicals are - MgSO4 and Mg3(PO4)2.With NO3 , it shall form Mg(NO3)2.All the bonds formed are ionic bonds because MgSO4,Mg3(PO4 ) and Mg(NO3)2 is an ionic compound since magnesium is a metal, and SO4 is considered a non-metal. Covalent compounds occur between two non-metals.
Ans 2 - Compound A is Magnesium and compound B is Sulphur.Magnesium is present in group 2 whereas Sulphur is present in group 16 in the modern periodic table.
Electronic Config. of Mg - 2,8,2 and that of Sulphur is 2,8,6. They shall form an ionic bond.