Prove that area of a rhombus is half the product of its diagonals.

  • 4

 

since the diagonals of a rhombus bisect each other at 90 degree.

since ABCD is a rhombus. OB=OD and OA=OC.

and ∠AOD= ∠AOB= ∠BOC= ∠COD= 90 degree.

area of ABCD can be divided in four parts.

area(ABCD)= area(ΔAOD)+area (ΔAOB)+ area(ΔBOC) +area(COD)

=1/2(product of diagonals)

  • 101

since the diagonals of a rhombus bisect each other at 90 degree.

since ABCD is a rhombus. OB=OD and OA=OC.

and ∠AOD=∠AOB=∠BOC=∠COD=90 degree.

area of ABCD can be divided in four parts.

area(ABCD)= area(ΔAOD) +area(ΔAOB) +area(ΔBOC) +area(COD)

=1/2(product of diagonals)

  • 30

above answers are absolutely right.

  • -4
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