Prove that area of a rhombus is half the product of its diagonals. Share with your friends Share 12 Gursheen kaur. answered this Here is the link to your query.https://www.meritnation.com/ask-answer/question/prove-that-area-of-the-rhombus-is-half-the-prodcut-of-the-2/areas-of-parallelograms-and-triangles/3373735 4 View Full Answer Himanshu answered this since the diagonals of a rhombus bisect each other at 90 degree.since ABCD is a rhombus. OB=OD and OA=OC.and ∠AOD= ∠AOB= ∠BOC= ∠COD= 90 degree.area of ABCD can be divided in four parts.area(ABCD)= area(ΔAOD)+area (ΔAOB)+ area(ΔBOC) +area(COD)=1/2(product of diagonals) 101 Himanshu answered this since the diagonals of a rhombus bisect each other at 90 degree.since ABCD is a rhombus. OB=OD and OA=OC.and ∠AOD=∠AOB=∠BOC=∠COD=90 degree.area of ABCD can be divided in four parts.area(ABCD)= area(ΔAOD) +area(ΔAOB) +area(ΔBOC) +area(COD)=1/2(product of diagonals) 30 Rajat Shukla answered this above answers are absolutely right. -4