PQ is tangent at a point C to a circle with center 0. If AB is a diameteer and angle CAB = 30 degree find angle PCA

Dear Student,
Please find below the solution to the asked query:

Given: PQ is a tangent. AB is a diameter, CAB=30°PCA=?In AOC,As, AO=CO                   GivenSo, CAO=OCA     Angles opposite to equal sides are equalor  CAB=OCAbut  CAB=30°So, OCA=30°        .....iSince, OCPQ      Tangent is perpendicular to the radius at point of contactPCO=90°OCA+PCA=90°30°+PCA=90°PCA=90°-30° PCA=60°

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