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Q). In fig., if AB is diameter of circle, then what is value of x?

Dear Student,

Here is the solution of your asked query:

Diameter AB forms a semicircle.And we know that angle substended by the diameter in a semicircle is 90°., so we have;ACB=90°Also, ABC=40°    {Given}We know that sum of angles of triangle is 180°. so we have;ABC+ACB+x=180°40°+90°+x=180°x=180°-130°=50°Therefore the value of x is 50°
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