Plz tell me this que fast ,???? Share with your friends Share 0 Aditi Gupta answered this Solution: (i) The reaction is as follows-M(s) + M+(aq)(1 M)→ M(aq)(0.05 M) + M(s) According to Nernst equation,Ecell = 0-2.303RTFlogM+(0.05M)M+ (1M) = 0 - 2.303RTF log (5×10-2) = positiveHence, Ecell = 0.70 Vand ∆G <0 for the feasability of the reaction.Hence, the correct option is (b).(ii)0.05 concentration is changed to 0.0025Ecell = 0 - log 0.00251 = 0 - 0.061 log 52 × 10-4 = 0.139 V ≈ 140 mV(iii) At equilibrium the emf becomes zero.(iv)The potential of an electrode change with change in concentration of ions, position of electrodes and voltage of the cell.Hence, the correct option is (d). 0 View Full Answer
