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$$\begin{gathered} \mathrm{As} \overrightarrow{\mathrm{a}} \mathrm{and} \overrightarrow{\mathrm{b}} \mathrm{are} \mathrm{in} \mathrm{plane} {\mathrm{P}}_1, \mathrm{hence} \\ \overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}} \mathrm{represents} \mathrm{normal} \mathrm{of} \mathrm{plane} {\mathrm{P}}_1 \\ \mathrm{Now} \\ \overrightarrow{\mathrm{c}} \mathrm{and} \overrightarrow{\mathrm{d}} \mathrm{are} \mathrm{in} \mathrm{plane} \mathrm{of} {\mathrm{P}}_2, \mathrm{hence} \\ \overrightarrow{\mathrm{c}}\times \overrightarrow{\mathrm{d}} \mathrm{represent} \mathrm{normal} \mathrm{of} \mathrm{plane} {\mathrm{P}}_2 \\ \mathrm{As} \\ \left(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}\right)\times \left(\overrightarrow{\mathrm{c}}\times \overrightarrow{\mathrm{d}}\right)=0 \\ \mathrm{Hence} \overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}} \mathrm{and} \overrightarrow{\mathrm{c}}\times \overrightarrow{\mathrm{d}} \mathrm{are} \mathrm{parallel}, \mathrm{i}.\mathrm{e}. \\ \mathrm{Normals} \mathrm{of} \mathrm{two} \mathrm{planes} \mathrm{are} \mathrm{parallel}. \\ \mathrm{Hence} \mathrm{planes} \mathrm{will} \mathrm{be} \mathrm{parallel} \mathrm{too}. \\ \mathrm{Hence} \mathrm{angle} \mathrm{between} \mathrm{planes} \mathrm{is} 0. \end{gathered}$$

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