Plz answer (ii) part... I am getting 6mm
Solution
given, width =a=0.6 mm=0.6*10-3 m
and first wavelength =600 nm
now for diffraction, we know, the distance of second bright fringe from central maximum =
given, width =a=0.6 mm=0.6*10-3 m
and first wavelength =600 nm
now for diffraction, we know, the distance of second bright fringe from central maximum =