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Solution:
(ii) Since the blue ball and black ball are equidistant from the origin.
$∴ |p| = 3 \Rightarrow p = - 3$
Thus, the black ball will be at ( $-$ 3, 0)

(iii) Abscissa of point R = 4
Also, the Ordinate of point G = 10
$∴$ Abscissa of point R $-$ Ordinate of point G = 4 $-$ 10
= $-$ 6

OR

(iii) Coordinates of origin = (0, 0)
Also, coordinates of point Y = (8, 6)
Therefore, the distance between point Y and the origin = $\sqrt{{(8 - 0)}^{2} + {(6 - 0)}^{2}}$
= 10

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