Pls solve this Pls solve this SECTION-A (1m X 3 = 3m) l) is tile midpoint Of side BC of then write the relation Set»een areas and If a parallelogram and a triangle are on the same base and between same tines then what is the ratio of areas of parallelogram and triangle? If a n•ctangle of length x units and breadth y units and a parallelogram whose adjacent sides x and z are on the same base and between same parallel lines. is the relation between their areas? In (he adjacent figure. AD divides BC in the ratio 2: 3. Show that ar(AABD) SECTION-B(2m X 3 = 6m) B s D c R In the adjacent figure S and T are the mid points of the sides PR and QR of the triangle PQR. If area of the triangle SQT is 6 sq.cnl then find the area of PQTS. and N are the mid points of the sides AB and AC of AABC. such that ar(MBC) = ar (NBC) Show that MN II BC. ABCD is a parallelogram. E is the midpoint of CD. Plove that ar(A8ED) = at EEC va-¯ABCD is a rectangle and P is any point inside the rectangle ABCD. tht ar (PAB) + ar(PCD) = ar(PAD) + ar(PBC). A If O is the midpoint of YD then show that ar(ABCO) — - ar(AFC) D c SECTION-DAIJIX3=i2) . Prove that parallelograms which are dn 'h? sarn•.• base and between same are equal in area. . Jf the medians of a MDC intersect at G then ;hat ar(MGB) : = -ar(MBC). Describe a justified plan to a triangle "hose ts quadrilateraJ, Share with your friends Share 0 Ashish Kumar answered this Dear student 7) Since E is the mid point of CD and triangle BCE and BED are on same base and between same parallel so area of triangle BEC = area of triangle BEDSo area of triangle BCD = 2× area of triangle triangle BEDNow area of triangle ABD = area of triangle BCD so area of quadrilateral ABED = area of triange ABD+area of triangle BED = 2area of triangle BEC+area of triangle BEC = 3 Area of triangle BEC Please ask other questions separately Regards 0 View Full Answer