Pls solve the 6th one:-
Pls solve the 6th one:-​ 6

Dear student
Force necessary to hold the left part with the right partF=P×(Area of circular cross section)(Area of circular cross section)=A=π×r2=π(R2-h2)P=is the electrostatic pressure =σ22σ=Q4πR2P=σ22=Q216π2R4×12F=Q216π2R4×12×π(R2-h2)=Q2(R2-h2)32πR4Regards

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