Pls solve the 6th one:- Pls solve the 6th one:- 6 Share with your friends Share 0 Sanjay Singh answered this Dear student Force necessary to hold the left part with the right partF=P×(Area of circular cross section)(Area of circular cross section)=A=π×r2=π(R2-h2)P=is the electrostatic pressure =σ22∈σ=Q4πR2P=σ22∈=Q216π2R4×12∈F=Q216π2R4×12∈×π(R2-h2)=Q2(R2-h2)32πR4∈Regards 0 View Full Answer