Pls qns 11 and 12

Solution

11- 
The net flux through a surface can be found by considering a closed Gaussian surface enclosing the charges. The flux is equal to the net charge divided by ε
0.

In the question, the enclosed by a Gaussian surface due to the dipole is = +q + (-q) = 0

Therefore, the flux is, ϕ = 0/ε0 = 0 

Kindly post other question in different thread.

  • 0
What are you looking for?