pls explain this question Share with your friends Share 0 Gursheen Kaur answered this Solution fx=2x + sin xDifferentiating wrt x on both sides, we getf'x=2 + cos x-1≤cos x≤1-1+2≤2+cos x≤1+21 ≤ 2 + cos x ≤3So, f'x>0 , for all real values of x .So, fxis one - onefx → ∞ as x→∞andfx → -∞ as x→-∞So, fx is onto. So, Range of f(x) = R ⇒ Range = Co - domain ⇒f(x) is onto. Thus, option (1) is correct. 0 View Full Answer