Pls answer this que to yiiiiii1009 Share with your friends Share 0 Anshu Agrawal answered this Solution: Given,x=t+5-1Velocity is,v=dxdt=ddtt+5-1=-1×t+5-1-1=-t+5-2⇒v=-x2...........1Acceleration is,a=dvdt=dvdx×dxdt=dvdx×vFrom 1a=ddx-x2×(-x2)=-2x×-x2=2x3a=2x3⇒a α x3⇒a α v3a α v32,Option B . 0 View Full Answer Manvitha Malapaka answered this Given as x=(t+5)^−1 velocity: v=dt/dx = −(t+5)^−2 acceleration: a=dt/dv = −2(t+5)^−3 v^3/2 = −(t+5)^−3 acceleration: a α v^3/2 0
