Pls ans 10

we know that the flux linked with a Gaussian surface is given as

Φ = E.ds = q/ε₀

here,

q = 8.85x10^-10 C

ε₀ = 8.85x10^-12 F/m

so,

Φ =  8.85x10^-10 /  8.85x10^-12 

thus, flux will be

Φ = 10² Nm²/C

(ii) 

The flux does not depend upon the size of the Gaussian surface but only on the charges enclosed. So, in this case also

Φ = 10² Nm²/C.