plot the points

Dear student,

We plot these points on x - y plane , As  : 

Now to find length of AC we use distance formula  

d = (x2 − x1)2 + (y2 − y1)2−−−−−−−−−−−−−−−−−−−−√x2 - x12 + y2 - y12
for AC  
x₁  = - 2  And x₂  = 2 
y₁  = 3 And y₂ = 0 
So,
AC   = (2 +2)2 + (0 −3)2−−−−−−−−−−−−−−−−√  = (4)2 + (−3)2−−−−−−−−−−√  = 16 + 9−−−−−−√  = 25−−√2 +22 + 0 -32  = 42 + -32  = 16 + 9  = 25  =  5 unit                      ( Ans )
And
for AC  D
x₁ = - 2  And x₂ = 2 
y₁ = 3 And y₂ = 6 
So,
AC   = (2 +2)2 + (6 −3)2−−−−−−−−−−−−−−−−√  = (4)2 + (3)2−−−−−−−−−√  = 16 + 9−−−−−−√  = 25−−√2 +22 + 6 -32  = 42 + 32  = 16 + 9  = 25  =  5 unit                      ( Ans )