Please solve and kindly tell..When and why do we take into account the pressure of the reacting specied in the nernst equation....??! Like we have in this question . Also are there any.other modifications in the nernst equation...??
pH = - log[H+]
3 = - log[H+]
-antilog 3 = [H+]
Therefore, [H+] = 10-3 M
Oxidation half reaction:
Fe(s) Fe2+ + 2e- ] X 2
4H+ + O2 + 4e- 2H2O
Number of electrons involved, n = 4
Cell potential is given as,
3 = - log[H+]
-antilog 3 = [H+]
Therefore, [H+] = 10-3 M
Oxidation half reaction:
Fe(s) Fe2+ + 2e- ] X 2
4H+ + O2 + 4e- 2H2O
Number of electrons involved, n = 4
Cell potential is given as,