Please solve 11th one

Let the money with Sonika be ₹x.

She spent $\frac{1}{2}$ of what she had on dresses and gave ₹2 to a beggar so the remaining money is $\frac{x}{2}-2$.

She spent $\frac{1}{2}$ of it on lunch and gave  ₹10 as a tip, so now the remaining tip : $\frac{1}{2}\left(\frac{x}{2}-2\right)-10$.

She spent $\frac{1}{2}$ of it on stationary and ₹6 as bus fare therefore the amount she has with her is

$$\begin{gathered} \frac{1}{2}\left[\frac{1}{2}\left(\frac{x}{2}-2\right)-10\right]-6=20 \\ \Rightarrow \frac{1}{2}\left[\frac{1}{2}\left(\frac{x}{2}-2\right)-10\right]=26 \\ \Rightarrow \frac{1}{2}\left(\frac{x}{2}-2\right)-10=52 \\ \Rightarrow \frac{1}{2}\left(\frac{x}{2}-2\right)=62 \\ \Rightarrow \frac{x}{2}-2=124 \\ \Rightarrow \frac{x}{2}=126 \\ \Rightarrow x=252 \end{gathered}$$

So, Sonika has ₹252.