Please help me with this.

Solution,
In case of a convex mirror.

\frac{1}{v} + \frac{1}{u} = \frac{1}{f} = c o n s \tan t o r, u^{- 1} = - v^{- 1} + c o n s \tan t T h u s, c o m p a r i n g w i t h t h e s t r a i g h t l i n e e q u a t i o n, y = m x + c t h e p l o t o f u^{- 1} v e r s u s v^{- 1} i s a s t r a i g h t l i n e h a v i n g a s l o p e m = - 1 a n d h a v i n g a n i n t e r c e p t, c = \frac{1}{f} . T h u s, a n s i s (C)