# please give the accurate answer

$currentthroughthebattery\phantom{\rule{0ex}{0ex}}i=\frac{V}{R}\left({e}^{\frac{-t}{RC/2}}\right)fromthetransirntcurrentthroughthebattery\phantom{\rule{0ex}{0ex}}andthevoltageofthebatteryiscons\mathrm{tan}tthatisV\phantom{\rule{0ex}{0ex}}workdone=Vit=\frac{{V}^{2}t}{R}\left({e}^{\frac{-t}{RC/2}}\right)\phantom{\rule{0ex}{0ex}}option4\phantom{\rule{0ex}{0ex}}Regards$

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