Please give detailed explanation. Choose correct option . Share with your friends Share 0 Shubham Ramesh Tiwari answered this Solution: ∠QPR=∠SRP=90° Since tangent subtends an angle of 90° with radius∠PXR=90° Semi circleLet ∠XPR=∅∠XRP=90-∅In ∆QPRtan90-∅=PQPRtan90-∅=PQ2r2r=PQtan90-∅ ...1In ∆PRStan ∅=RSPR2r=RStan ∅ ...2On multiplying 1 and 2 , we get4r2=PQtan90-∅.RStan ∅4r2=PQ.RScot ∅ tan ∅4r2=PQ.RS2r=PQ.RSSo, correct answer is 1 PQ.RS ANS... 0 View Full Answer
