Please answer this question fast -

Solution
Let the three consecutive multiples of 7 be 7x, 7x + 7 and 7x + 14
Now, ATQ,
7x + 7x + 7 + 7x + 14 = 693
21x + 21 = 693
21x = 693 - 21
21x = 672
x = $\frac{672}{21}=32$
So, multiples of 7 are
7x = 7 × 32 = 224
7x + 7 = (7 × 32) + 7 = 224 + 7 = 231
7x + 14 = (7 × 32) + 14 = 224 + 14 = 238