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Solution :

$We have, p (x) = x^{2} - 2 x - 8 Now, zeroes of p (x) are given by solving the equation : p (x) = 0 \Rightarrow x^{2} - 2 x - 8 = 0 \Rightarrow x^{2} - 4 x + 2 x - 8 = 0 \Rightarrow x (x - 4) + 2 (x - 4) = 0 \Rightarrow (x + 2) (x - 4) = 0 \Rightarrow x + 2 = 0 or x - 4 = 0 \Rightarrow x = - 2 or x = 4$

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