Please answer question no 12 in the attached file

Dear student

a) sinθ2=12a^-b^We have:a^-b^2=a^-b^.a^-b^   as a.a=a2a^-b^2=a^.a^-a^.b^-b^.a^+b^.b^a^-b^2=a^2-2a^.b^+b^2   as a^.b^=b^.a^a^-b^2=a^2-2a^b^cosθ+b^2      as a^.b^=a^b^cosθ a^-b^2=2-2cosθ    asa^= b^=1a^-b^2=21-cosθ=22sin2θ2=4sin2θ2sin2θ2=14a^-b^2sinθ2=12a^-b^Hence proved.



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