Please answer 48 and 49 with explanation.       

49. Total work done on the gas in two stage compression is :
(a) 40
(b) 80
​​​​​​​(c) 160
​​​​​​​(d) 20              

Dear student
Answer of Q.No. 49 is as follows
Work done for the first process :

w = -nRT(2.303) log (P1/P2)

w =-2*0.0821*log (2/20)

w=0.1642 bar -L

work done for II process 

For irreversible compression system :

wA = pext(V2-V1 ) 
wB= pext(V2-V1 ) 

 Assuming  value of V= 8L as you haven't mentioned it in the question.

 V1 = 4L

 WA = 10(8-4) = 40 Lbar.

 WB = 20(8-4) = 80 Lbar.

Hence total work done in second stage compression is 80 i.e. Option B is correct answer
Ask Q.No. 48 in next thread so that we can answer you.
Hope it is clear
Regards

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