Please answer 20th question
Q.20. If ABCDEF is a regular hexagon, then AD + EB + FC equals
(a) zero
(b) 2 AB
(c) 4 AB
(d) 3 AB

Dear student
 
4AB is the answer.


AD=2BCEB=2FAFC=2AB

AD+EB=2BC+FA=2AO+FA            BC=AO

In triangle AOF,

FA+AO+FO=0FA+AO=FOAD+EB=2FO

And AB=FO

AD+EB=2ABAD+EB+FC=2AB+2AB=4AB
Regards

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