Particle A makes a perfectly elastic collision with another particle B at rest They fly apart in opposite direction - Physics - Work Energy And Power

Question

Particle A makes a perfectly elastic collision with another
particle B at rest They fly apart in opposite direction with equal
speeds If their masses are mA & mB
respectively, then:-

a) 2mA=mB
b) 3mA=mB
c) 4mA=mB
d) (3)1/ 2mA=mB

Govind · Accepted Answer

Givenm1=mA, m2=mB, u1=u, u2=0Applying principle of conservation of  kinetic energym1u+0=m1v+m2-v=m1-m2v      
1   ⇒uv=m1-m2m1      
2From the principle of conservation of energy, we have12m1u2=12m1+m2v2     
3Dividing 3 by 1, we getuv=m1+m2m1-m2     
4Comparing equation 2 and 4, we havem1+m2m1-m2=m1-m2m1On solving we getm1m2=13 or mAmB=13

Particle A makes a perfectly elastic collision with another particle B at rest. They fly apart in opposite direction with equal speeds.. If their masses are mA & mB respectively, then:- a) 2mA=mB b) 3mA=mB c) 4mA=mB d) (3)1/ 2mA=mB

Particle A makes a perfectly elastic collision with another particle B at rest. They fly apart in opposite direction with equal speeds.. If their masses are m_A & m_Brespectively, then:-

a) 2m_A=m_B
b) 3m_A=m_B
c) 4m_A=m_B
d) (3)^1/ ²m_A=m_B